SOLUTION: The oldest child in a family is 5 years older than her brother. The mother is 1 year younger than twice the sum of her children's ages, and the father's age equals the mother's age
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Question 828564: The oldest child in a family is 5 years older than her brother. The mother is 1 year younger than twice the sum of her children's ages, and the father's age equals the mother's age plus the son's age. If the sum of all four ages is three times a prime number and the mother was younger than 50 when she had her second child, how old is the daughter?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
g=b+5,
2*(g+b)-1=m,
f=m+b,
m-g<50,
http://www.algebra.com/algebra/homework/word/age/Age_Word_Problems.faq.question.802717.html
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