SOLUTION: Four years ago, the sum of the ages of Tom and Dick was 45. Six years from now, twice Dick’s age will be 28 more than Tom’s age then. How old is Tom now?
Algebra.Com
Question 823401: Four years ago, the sum of the ages of Tom and Dick was 45. Six years from now, twice Dick’s age will be 28 more than Tom’s age then. How old is Tom now?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
t+d-8=45
t+d=53
2(d+6)=28+t+6
2d+12=t+34
2d-t=22
t+d=53
add
3d=75
d = 25, t = 28
RELATED QUESTIONS
"Four years ago, the sum of the ages of May and Ann was 45. Six years from now,... (answered by josmiceli)
Four years ago, the sum of the ages of A & B was 45. Six years from now, twice B's age... (answered by Nate)
Judy age now is twice tom's age decreased by 10. In four years, the sum of Judy's age and (answered by josgarithmetic)
Last year Dick was twice as old as Jane. Four years ago the sum of Dick's age and... (answered by stanbon)
The sum of the ages of Tom and Chloe is 72 years. 10 years ago, Tom's age was 3 times... (answered by MathLover1)
Three times the sum of Jim’s and Tom’s ages is equal to twelve times the difference of... (answered by josgarithmetic)
three years ago Tom was twice as old as Jean, and in two years the sum of their ages will (answered by ankor@dixie-net.com)
THE SUM OF TOM'S, DICK'S AND HARRY'S AGES IS 31. TOM IS TWICE AS OLD AS DICK. HARRY IS 6... (answered by ewatrrr)
Tom is twice as old as Dick was when Harry was one year younger than Tom is now.
Dick is (answered by Edwin McCravy)