SOLUTION: The present age of a man is 7x years and that of his son is (2x-1) years. When the man was (x square - 5) years old, his son was (x+1) years. Then present age of his son is-
Algebra.Com
Question 822582: The present age of a man is 7x years and that of his son is (2x-1) years. When the man was (x square - 5) years old, his son was (x+1) years. Then present age of his son is-
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
7x-(2x-1)=x^2-5-(x+1)
7x-2x+1=x^2-5-x-1
5x+1=x^2-x-6
x^2-6x-7=0
(x-7)*(x+1)=0
x=7
father is 49
son is 14-1=13
check
49-5=44
8=13-5
ok
RELATED QUESTIONS
five years ago, a man was five times as old as his son. two years hence, the man will we... (answered by lwsshak3,MathTherapy)
A man is 4 years older than his wife and 5 times as old as his son. When the son was... (answered by mananth,lwsshak3)
A man is 4 years older than his wife and 5 times as old as his son. When the son was... (answered by ankor@dixie-net.com)
two years ago,a man was five times as old as his son. two years later,his age be 8 more... (answered by JulietG)
a man is 4 times old his son and their ages add up to 40 years. What was the age of son 5 (answered by richwmiller)
A man is 6 times as old as his son. 20 years later, the man will be twice as old as his... (answered by Alan3354)
A man is six times as old as his son. Twenty years later, the man will be twice as old as (answered by lwsshak3)
P years ago a man age was(q+r)times that of his son who was then r years old.how old is... (answered by greenestamps)
A man is 5 times as old as his son, 2 years ago the sum of square of their ages was 114,... (answered by Alan3354)