SOLUTION: The age of a father is 5 more than twice of his son's age. The age of the mother is the sum of her son's age and one third of the father's age. The sum of all their ages is 100. Fi

Question 817882: The age of a father is 5 more than twice of his son's age. The age of the mother is the sum of her son's age and one third of the father's age. The sum of all their ages is 100. Find their ages.

Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
f = 2s + 5
m = s + f/3
m + f + s = 100
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m + f + s = 100
s + f/3 + 2s + 5 + s = 100
s + (2s + 5)/3 + 2s + 5 + s = 100
s + (2/3)s + 5/3 + 2s + 5 + s = 100
4s + (2/3)s = 100 - 5/3 - 5
(12/3)s + (2/3)s = 300/3 - 5/3 - 15/3
(14/3)s = 280/3
14s = 280
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s = 20
f = 45
m = 35
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