SOLUTION: David is twice as old as his daughter. In 14 years, David's age will be three times what his daughter's age was 6 years ago. How old are they now?
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Question 813487: David is twice as old as his daughter. In 14 years, David's age will be three times what his daughter's age was 6 years ago. How old are they now?
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
d = 2k
d + 14 = 3(k - 6)
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d + 14 = 3(k - 6)
d + 14 = 3k - 18
2k + 14 = 3k - 18
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kid = 32
dave = 64
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