SOLUTION: Bob is 25 years younger than his father and 27 years older than his son. What are their ages. The sum must total 100.
Father
Bob
Son
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Question 813173: Bob is 25 years younger than his father and 27 years older than his son. What are their ages. The sum must total 100.
Father
Bob
Son
Found 2 solutions by erica65404, MathTherapy:
Answer by erica65404(394) (Show Source): You can put this solution on YOUR website!
father = x
Bob = y
Son = z
x = 25 + y
y = y
z =y - 27
x + y + z = 100
Bob is 34. since his father is 25 years older, his father is 59. Since his son is 27 years younger, his son is 7.
34 + 59 + 7 = 100
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
Bob is 25 years younger than his father and 27 years older than his son. What are their ages. The sum must total 100.
Father
Bob
Son
Let Bob's father's age be F
Then Bob's age = F - 25
Bob's son's age: F - 25 - 27, or F - 52
All ages total 100, so: F + F - 25 + F - 52 = 100
3F - 77 = 100
3F = 177
F, or Bob's father's age = , or
Bob's age: 59 - 25, or
Bob's son's age: 34 - 27, or
You can do the check!!
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