SOLUTION: Jack is 4 times as old as Lacy. 6 years from now the sum of their ages will be 87. How old are they now?
Algebra.Com
Question 783235: Jack is 4 times as old as Lacy. 6 years from now the sum of their ages will be 87. How old are they now?
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
Jack is 4 times as old as Lacy
J = 4L
6 years from now the sum of their ages will be 87.
J + 6 + L + 6 = 87
Replace J with 4L from 1st equation
4L + 6 + L + 6 = 87
Collect like terms.
4L + L = 87 - 12
5L = 75
L = 15
Current ages:
Lacy = 15 years old
Jack = 60 years old.
Hope this helps.
:-)
RELATED QUESTIONS
Jack is 4 times as old as Lacy. 6 years from now the sum of their ages will be 67. How... (answered by stanbon)
jack is two times as old as lacy. 6 years from now the sum of their ages will be 30. How... (answered by Jamil Ahmed Tanjum)
Jack is
3
times as old as Lacy.
6
years from now the sum of their ages will be... (answered by josgarithmetic)
Jack is 4 times as old as Lacy. 8 years from now the sum of their ages will be 81 . How (answered by graphmatics)
Jack is 3 times as old as Lacy. 4 years from now the sum of their ages will be 68. How... (answered by ewatrrr)
Jack is 4 times as old as Lacy. 9 years from now the sum of their ages will be 63. How... (answered by addingup)
Jack is 4 times as old as Lacy. 8 years from now the sum of their ages will be 76. How... (answered by josmiceli)
Jack is 4 times as old as lacy. 5 years from now the sum of their ages will be 85. How... (answered by Cromlix)
Jack is 2 times as old as Lacy. 8 years from now the sum of their ages will be 55. How... (answered by Maths68)