SOLUTION: Jack is 4 times as old as Lacy. 6 years from now the sum of their ages will be 67. How old are they now?
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Question 781598: Jack is 4 times as old as Lacy. 6 years from now the sum of their ages will be 67. How old are they now?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Jack is 4 times as old as Lacy. 6 years from now the sum of their ages will be 67. How old are they now?
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Equations:
j = 4L
j+6 + L+6 = 67
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Substitute for "j" and solve for "L"::
4L + 6 + L + 6 = 67
5L = 55
Lacy = 11 yrs (her age now)
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Jack = 4L = 44 yrs (his age now)
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Cheers,
Stan H.
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