SOLUTION: Rene is 6 years older than her younger sister. After ten years, the sum of their ages will be 50 years. Find their present ages.
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Question 775968: Rene is 6 years older than her younger sister. After ten years, the sum of their ages will be 50 years. Find their present ages.
Answer by tanjo3(60) (Show Source): You can put this solution on YOUR website!
Let n be Rene's current age. Then, her sister's age is (n - 6).
Our equation is then:
n + 10 + (n - 6) + 10 = 50
Simplify.
2n + 14 = 50
2n = 36
n = 18
Therefore, Rene is currently 18 years old and her younger sister is 12.
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