SOLUTION: two years ago a father was five times as old as his son.two years later his age will be 8 more than 3 times the age of the son. find the present ages of father and son

Question 770658: two years ago a father was five times as old as his son.two years later his age will be 8 more than 3 times the age of the son. find the present ages of father and son

Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
Father = 5 * S
F = 5S
F = 5S
Two years later
F + 2 = 8 + 3(S + 2)
Replace F with 5S
5S + 2 = 8 + 3(S + 2)
5S + 2 = 8 + 3S + 6
5S - 3S = 8 + 6 - 2
2S = 12
S = 6
Present ages:
Son = 8 yrs old.
Father = 32 years old.
Hope this helps.
:-)
RELATED QUESTIONS
two years ago kumar a father was 5 times as old as a son.2 years later,his age will be 8... (answered by richwmiller)

two years ago , a father was five times old as his son . two years later from today his... (answered by ankor@dixie-net.com)

Two years ago, a man was five times as old as his son. Two years later, his age will be 8 (answered by josmiceli)

two years ago,a man was five times as old as his son. two years later,his age be 8 more... (answered by JulietG)

A Year hence a Father will be Five times as Old as his Son. Two years ago , The father... (answered by addingup,MathTherapy)

1.Two years ago, Greg was 3 times as old as his brother. In four years, he will be only... (answered by AnlytcPhil)

Ten years ago a father was seven times as old as his son, two years hence twice his age... (answered by ankor@dixie-net.com)

two years ago father was three times as old as his son and two years hence twice his age... (answered by TimothyLamb)

Ten years ago a father was seven times as old as his son, two years hence twice his age... (answered by vleith)