SOLUTION: The length of a rectangle is 3 times its width. If the length is increased by 2 inches and the width by 1 inch, the new perimeter is 62 inches. What is the width before the increas
Algebra.Com
Question 761128: The length of a rectangle is 3 times its width. If the length is increased by 2 inches and the width by 1 inch, the new perimeter is 62 inches. What is the width before the increase
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
Width = x
Length = 3x
New sizes
Width = x + 1
Length = 3x + 2
Perimeter = 2*length = 2*width
62 = 2(3x + 2)+ 2(x + 1)
62 = 6x + 4 + 2x + 2
62 = 8x + 6
8x = 56
x = 7
Width was 7 inches before increase.
Hope this helps.
:-)
RELATED QUESTIONS
the length of rectangle is 3 times its width. if the length is increased by 2 inches and... (answered by chessace)
the length of a rectangle is three times its width. if the width is diminished by 1 inch... (answered by checkley77)
Suppose that the length of a certain rectangle is three times its width. If the length... (answered by richwmiller)
please help me solve this problem: the dimensions of a rectangle are such that its... (answered by mananth)
If the length of a rectangle is decreased by 2 inches and its width is increased by 2... (answered by ankor@dixie-net.com)
the length of a rectangle is 1 inch less than 3 times the width. if the length is... (answered by Finavon)
the length of a rectangle is 3 times the width. if the length is increased by 6 inches... (answered by josgarithmetic)
The length of a rectangle is 4 inches greater than twice its width. If the length and... (answered by ReadingBoosters)
a rectangle has a width of 5 inches and a length of 7 inches. If both its length and... (answered by gurjit747)