SOLUTION:
Hi , do help me with this few problems sums , thank you :)
A father is 30 years older than his son. In 6 years' time ,
he will be twice as old as his son. What are their pres
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Question 741232:
Hi , do help me with this few problems sums , thank you :)
A father is 30 years older than his son. In 6 years' time ,
he will be twice as old as his son. What are their present ages ?
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
F=S+30
F+6=2S
(S+30)+6=2S
S+36=2S
S-2S=-36
-S=-36
S=36 YEARS OLD FOR THE SON.
F=36+30
F=66 YEARS OLD FOR THE FATHER.
66+6=2*36
72=72
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