SOLUTION:
Present age of the father is 3 times that of his sons. The sum of that ages 10 years ago is as much as their present age of the father. Find the ages
Algebra.Com
Question 739732:
Present age of the father is 3 times that of his sons. The sum of that ages 10 years ago is as much as their present age of the father. Find the ages
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
F=3X
S=X
3X-10+X-10=3X
3X-3X+X=10+10
X=20 AGE OF THE SON NOW.
3*20=60 AGE OF THE FATHER NOW.
PROOF:
60-10+20-10=60
80-20=60
60=60
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