SOLUTION: Bob is seven years younger than twice Susan's age. the sum of their ages is 29. How old is each?

SOLUTION: Bob is seven years younger than twice Susan's age. the sum of their ages is 29. How old is each?

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Question 723764: Bob is seven years younger than twice Susan's age. the sum of their ages is 29. How old is each?
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
m for bob, f for susan.
m=2f-7 and m+f=29. Various ways to go. (2f-7)+f=29, 2f+f-7=29, 3f-7=29, 3f=29+7, 3f=36, . Do the rest.
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