SOLUTION: 2. The ages of Steve’s three brothers are consecutive even integers. Find their ages if the sum of their ages is 72.

Algebra.Com
Question 721713: 2. The ages of Steve’s three brothers are consecutive even integers. Find their ages if the sum of their ages is 72.

Answer by htmentor(1343)   (Show Source): You can put this solution on YOUR website!
Let n = the age of the middle brother
Then the ages of the other two are n-2 and n+2
The sum of the ages is 72:
3n = 72
n = 24
So their ages are 22,24,26

RELATED QUESTIONS

THE AGES OF THREE BROTHERS ARE CONSECUTIVE *EVEN* INTEGERS. THE SUM OF THEIR AGES IS 54. (answered by stanbon,haileytucki)
The ages of three brothers are consecutive odd integers. The sum of their ages is 111.... (answered by Fombitz)
The ages of three sisters are consecutive integers. The sum of their ages is 66.... (answered by Alan3354)
The ages of three brothers are consecutive odd integers. The sum of their ages is 129.... (answered by Alan3354,MathTherapy)
the ages of Eddy, Ashley and Juan are consecutive integers. The sum of their ages is 126. (answered by Alan3354)
The ages of three brothers are consecutive odd integers.The sum of their ages is 111.How... (answered by texttutoring)
The present ages of 4 brothers are consecutive multiples of three. 5 years ago the sum of (answered by htmentor)
three brothers have ages that are consecutive multiples of five, the sum of their ages... (answered by stanbon)