SOLUTION: A father is twice his son's age. Twelve years ago, the father was three times as old as his son. How old is each person now.
I know the answer but not the equation.
NOW: fa
Algebra.Com
Question 716095: A father is twice his son's age. Twelve years ago, the father was three times as old as his son. How old is each person now.
I know the answer but not the equation.
NOW: father is 48 and son is 24.
12 years ago: father was 36 and son was 12
What equation do i use please?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
let son's age =x
father's age = 2x
12 years ago
(2x-12)= 3(x-12)
2x-12=3x-36
2x-3x=-36+12
-x=-24
x= 24
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