SOLUTION: Anne is twice the age of Jim. In six years, their ages will total 60. How old is each now? I tried doing it but this came out: A+J+6+6=60 A+J+12=60 A+J=48 2J+J=48 (because A=2J

Question 710892: Anne is twice the age of Jim. In six years, their ages will total 60. How old is each now? I tried doing it but this came out:
A+J+6+6=60
A+J+12=60
A+J=48
2J+J=48 (because A=2J)
3J=48
J=12, A=24, but it's wrong!
Found 2 solutions by stanbon, lwsshak3:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Anne is twice the age of Jim. In six years, their ages will total 60. How old is each now?
-------
Equations:
a = 2j
(a+6) + (2j+6) = 60
----
Substitute for "a" and solve for "j":
(2j+6) + 2j+6 = 60
4j + 12 = 60
4j = 48
jim = 4 yrs (jim's age now)
------------------
Solve for "a":
a = 2j
a = 8 yrs (anne's age now)
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Cheers,
Stan H.
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Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Anne is twice the age of Jim. In six years, their ages will total 60. How old is each now?
**
let x=Jim's age
2x=Anne's age
In 6 years:
x+6=Jim's age
2x+6=Anne's age
x+6+2x+6=60
3x=60-12
3x=48
x=16
2x=32
Jim's age=16
Anne's age=32
You just missed the last step!
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