SOLUTION: rebecca is four years older than jake. Five years ago she was twice as old as he was. Find their ages now.

Algebra.Com
Question 668487: rebecca is four years older than jake. Five years ago she was twice as old as he was. Find their ages now.

Answer by swincher4391(1107)   (Show Source): You can put this solution on YOUR website!
Let r be the age of Rebecca. Let j be the age of Jake.
Rebecca is four years older than Jake: r = j+4
Five years ago she was twice as old as he was: r-5 = 2(j-5)
Substitute j+4 for r.
j+4-5 = 2(j-5)
j-1 = 2j -10
9 = j
r = 9 +4 = 13
So Jake is 9 and Rebecca is 13.

RELATED QUESTIONS

Monica is four years older than Kate. Five years ago, she was twice as old as Kate was.... (answered by macston)
Jake is five years older than laura. Four years ago jake was twice as old as laura was... (answered by lwsshak3)
Help me solv this? Jennifer is six years older than Sue. In four years she will be twice (answered by ptaylor)
Jessica is 3 years older than Rebecca. In 5 years she will be 3 times as old as Rebecca... (answered by jorel1380)
John is 4 years older than Kate. In 7 years he will be twice as old as Kate was five... (answered by Earlsdon)
Mr.Munch is twice as old as his daughter. In two years, he will be four times as old as... (answered by lwsshak3)
Phil is 24 years older than Will. Four years ago he was seven times as old as Will was... (answered by josmiceli)
Jennifer is 6 years older than Sue. In 4 years, she will be twice as old as Sue was 5... (answered by edjones)
jenifer is 6 years older than sue. in 4 years she will be twice as old as sue was 5 years (answered by solver91311)