SOLUTION: man's age + his wife's age=63.
He is twice as old as his wife was when he was his wife's present age.
All I can get is he =x she=y
x=2(y-[x-y]) x+y=63
What do
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Question 658604: man's age + his wife's age=63.
He is twice as old as his wife was when he was his wife's present age.
All I can get is he =x she=y
x=2(y-[x-y]) x+y=63
What do I do now?
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
man's age + his wife's age=63.
He is twice as old as his wife was when he was his wife's present age.
All I can get is he =x she=y
x=2(y-[x-y]) x+y=63
What do I do now?
x + y = 63 ----- x = 63 - y ------ eq (i)
x = 2[y – (x – y)]
x = 2(y – x + y)
x = 2(2y - x)
x = 4y – 2x
x + 2x – 4y = 0
3x - 4y = 0 ------ eq (ii)
3(63 - y) - 4y = 0 -------- Substituting 63 - y for x in eq (ii)
189 - 3y - 4y = 0
- 7y = - 189
y, or wife's age = , or
Now substitute 27 for y in eq (i) and you'll find man's age.
You can also do your own check!!
Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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