SOLUTION: Hello I have done 7 out of 10 problems these are giving me some problems. 1 A right tringle has sides of 20cm and 15 cm. What is the length of the hypothenus. Thanks 6 Simp

Question 65188: Hello I have done 7 out of 10 problems these are giving me some problems.
1 A right tringle has sides of 20cm and 15 cm. What is the length of the hypothenus. Thanks
6 Simply 2(sqrt12)/4(sqrt27). Thanks
10 Find the distance between (4,0 and (-9,0)
Thanks for your help and have a happy Holiday.
Found 2 solutions by checkley71, Earlsdon:
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
a^2+b^2=c^2 c being the hypotenuse
20^20=15*15=c^2
400+225=c^2
c^2=625
c=25
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2sqrt12/4sqrt27 factor sqrt 12=sqrt4*3 & sqrt 27=sqrt9*3
2*2sqrt3/4*3sqrt3
4sqrt3/12sqrt3 factor out the 4 & the sqrt 3 leaves you with
1/3
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distance between (4,0)& (-9,0)is
4-(-9)=4+9=13 is the distance between thwese two points
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HAVE A MERRY CHRISTMAS & A HAPPY NEW YEAR
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
11. Find the length of the hypotenuse if the two legs are 20cm and 15cm.
Remember that in a right triangle, the lengths of the sides are in proprtion to: 3, 4, and 5, and the hypotenuse is always the longest side.
So:
15 = 3*5
20 = 4*5
x = 5*5 = 25
The hypotenuse is 25cm.
6. Simplify:
Cancel 2 in the top and bottom.
Simplify the square roots.

Cancel where appropriate.

10. The distance between two points, (x1, y1) and (x2, y2) is given by:
Applying this to your two points:(4, 0) and (-9, 0)

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