SOLUTION: a mother is presently 5 years older than twice her daughter's sge. 10 years ago the product of the mother and daughter's age was equal to 125.What is the mom's age?

Question 647801: a mother is presently 5 years older than twice her daughter's sge. 10 years ago the product of the mother and daughter's age was equal to 125.What is the mom's age?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
a mother is presently 5 years older than twice her daughter's sge. 10 years ago the product of the mother and daughter's age was equal to 125.What is the mom's age?
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Equations:
m = 2d + 5
(m-10)(d-10) = 125
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Substitute for "m" and solve for "d:
(2d+5-10)(d-10) = 125
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(2d-5)(d-10) = 125
2d^2-25d+50-125 = 0
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2d^2 - 25d -75 = 0
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(d-15)(2d+5) = 0
d = 15 (daughter's age)
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m = 2d+5 = 35 (mom's age)
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Cheers,
Stan H.
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