SOLUTION: Paul is 11 years younger than Wendy. In 10 years, Wendy will be twice as old as Paul. How old is Paul now?

Question 636450: Paul is 11 years younger than Wendy. In 10 years, Wendy will be twice as old as Paul. How old is Paul now?
Answer by Maths68(1474) (Show Source): You can put this solution on YOUR website!
Let
Present age of Paul = p years old
Present age of Wendy = w years old

Paul is 11 years younger than Wendy.
w=p+11............(1)
In 10 years,
Paul will be = p+10 years old
Wendy will be = w+10 years old
Then
Wendy will be twice as old as Paul
w+10=2(p+10)
w+10=2p+20
w=2p+20-10
w=2p+10................(2)
Put the value of w from (1) to (2)
p+11=2p+10
p-2p=10-11
-p=-1
p=1
Put the value of p in (1)
w=p+11............(1)
w=1+11
w=12

Present age of Paul = p = 1 year old
Present age of Wendy = w = 12 years old
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