SOLUTION: The age of a father was 6 times the age of his son two years ago. After six years the ratio of their ages was 10:3. what is the age of father now?

Question 635690: The age of a father was 6 times the age of his son two years ago. After six years the ratio of their ages was 10:3. what is the age of father now?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The age of a father was 6 times the age of his son two years ago.
After six years the ratio of their ages was 10:3.
what is the age of father now?
:
Let f = father's present age
let s = son's age
:
"The age of a father was 6 times the age of his son two years ago."
f - 2 = 6(s - 2)
f - 2 = 6s - 12
f = 6s - 12 + 2
f = 6s - 10
:
"After six years the ratio of their ages was 10:3."
=
cross multiply
10(s+6) = 3(f+6)
10s + 60 = 3f + 18
10s + 60 - 18 = 3f
10s + 42 = 3f
Replace f with (6s-10)
10s + 42 = 3(6s-10)
10s + 42 = 18s - 30
42 + 30 = 18s - 10s
72 = 8s
s = 72/8
s = 9 yrs is the son's age
then
f = 6s - 10
f = 6(9) - 10
f = 54 - 10
f = 44 yrs is the father's age
:
:
:
Confirm that
= =
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