SOLUTION: A man is 4 times older than his son.5years ago the product of their age was 175. Find their present ages

Question 626975: A man is 4 times older than his son.5years ago the product of their age was 175. Find their present ages
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A man is 4 times older than his son.5years ago the product of their age was 175. Find their present ages
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Equations:
m = 4s
(m-5)(s-5) = 175
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Substitute for "m" and solve for "s":
(4s-5)(s-5)= 175
4s^2 -25s + 25 = 175
4s^2 - 25s - 150 = 0
(x-10)(4x+15) = 0
Positive solution:
s = 10 (son's age)
m = 4s = 40 (man's age)
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Cheers,
Stan H.
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