SOLUTION: a man is twice as old as his son. let Y the age of the man and X the age of the son. Now, their age difference/gap is 32, find their present ages.

Question 625644: a man is twice as old as his son. let Y the age of the man and X the age of the son.
Now, their age difference/gap is 32, find their present ages.
Answer by reynard2007(52) (Show Source): You can put this solution on YOUR website!

If y is the age of the man and he is twice as old as his x-year old son, we can symbolize the the man's age as 2x. We have to express everything in terms of x because we would need two equations if we use two variable.

We now setup the equation: 2x-x=32 ==> x=32
So, the man is 64 while his son is 32 years old.
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