# SOLUTION: Two years ago, a father was 8 times as old as his son. Ten years from now, the ratio of their ages will be 10:3. What is the father's age today? Thanks.

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 Click here to see ALL problems on Age Word Problems Question 602276: Two years ago, a father was 8 times as old as his son. Ten years from now, the ratio of their ages will be 10:3. What is the father's age today? Thanks.Found 2 solutions by scott8148, ankor@dixie-net.com:Answer by scott8148(6628)   (Show Source): You can put this solution on YOUR website!"Two years ago, a father was 8 times as old as his son" ___ f - 2 = 8(s - 2) ___ f = 8s - 14 "Ten years from now, the ratio of their ages will be 10:3" ___ (f + 10) / (s + 10) = 10 / 3 ___ 3f + 30 = 10s + 100 multiplying 1st equation by 10 ___ 10f = 80s - 140 multiplying 2nd equation by 8 ___ 24f + 240 = 80s + 800 subtracting equations ___ 24f + 240 - 10f = 80s + 800 - 80s - -140 ___ 14f + 240 = 940 Answer by ankor@dixie-net.com(15646)   (Show Source): You can put this solution on YOUR website!let f = father's present age let s = son's present age : Write an equation for each statement: : "Two years ago, a father was 8 times as old as his son." f - 2 = 8(s-2) f - 2 = 8s - 16 f = 8s - 16 + 2 f = 8s - 14 : " Ten years from now, the ratio of their ages will be 10:3." = cross multiply 3(f+10) = 10(s+10) 3f + 30 = 10s + 100 3f = 10s + 100 - 30 3f = 10s + 70 Replace f with (8s-14) 3(8s-14) = 10s + 70 24s - 42 = 10s + 70 24s - 10s = 70 + 42 14s = 112 s = 112/14 s = 8 yrs is son's age then f = 8(8) - 14 f = 64 - 14 f = 50 yrs is father's age today