SOLUTION: Cecile is now four times as old as daisy. Five years ago, the sum of their ages was 45. How old is each now?
Algebra.Com
Question 571491: Cecile is now four times as old as daisy. Five years ago, the sum of their ages was 45. How old is each now?
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Cecile is now four times as old as daisy. Five years ago, the sum of their ages was 45. How old is each now?
**
let x=Daisy's age now
4x=Cecile's age now
5 years ago,
Daisy's age =x-5
Cecile's age=4x-5
..
x-5+4x-5=45
5x=55
x=11
4x=44
ans:
Daisy's age now=11
Cecile's age now=44
RELATED QUESTIONS
Cecile is now four times as old as daisy . Five years ago , the sum of their two ages was (answered by josmiceli)
Cecile is now four times as old as Daisy.Five years ago, the sum of their ages was 45.How (answered by josmiceli,Caxxx)
Alvin is now four times as old as Benjamin. Five years ago, the sum of their ages was 45... (answered by josmiceli)
A man is now four times as old as his brother. five years ago the sum of their ages was... (answered by richwmiller)
Kevin is now four times as old as mark. Five years ago,
The sum of their ages was 45.... (answered by MathLover1,MathTherapy)
Alvin is now 4 times as old as benjamin. Five years ago, the sum of their ages was 45... (answered by addingup)
Vicky is now 4 times as old as Cristy. five years ago,the sum of their ages was 45. how... (answered by piggy278)
Vicky is now 4 times as old as Cristy. five years ago,the sum of their ages was 45. how... (answered by stanbon)
Vicky is now 4 times as old as Cristy. Five years ago, the sum of their ages was 45. How... (answered by ikleyn)