SOLUTION: the sides of a triangle can be represented as 2x+2, 4x+24, and 6x-2. The sides of a square can be represented as 2x+10. if the perimeters of both shapes are equal, what is the valu

Question 551455: the sides of a triangle can be represented as 2x+2, 4x+24, and 6x-2. The sides of a square can be represented as 2x+10. if the perimeters of both shapes are equal, what is the value of x?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
the sides of a triangle can be represented as 2x+2, 4x+24, and 6x-2.
:
the perimeter of the triangle
p = 2x+2 + 4x+24 + 6x-2
combine like terms
p = 12x+24
:
The sides of a square can be represented as 2x+10.
the perimeter of the square
P = 4(2x+10)
P = 8x + 40
:
if the perimeters of both shapes are equal, what is the value of x?
12x + 24 = 8x + 40
12x - 8x = 40 - 24
4x = 16
x = 4
;
:
see if the works
12(4) + 24 = 72
8(4) + 40 = 72
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