SOLUTION: michelle's age is 10 years less than 5 times sarah's age. If the sum of their age is 44 years, find their ages.
Algebra.Com
Question 547856: michelle's age is 10 years less than 5 times sarah's age. If the sum of their age is 44 years, find their ages.
Found 2 solutions by mathie123, JBarnum:
Answer by mathie123(224) (Show Source): You can put this solution on YOUR website!
Let M be michells age and S be sarah's age. From the question we can make up two equations:
(1)
(2)
This is just a system of equations with two unknowns
Substituting (1) into (2) we get
Now substituting this value back into (1) we get:
So Michelle is 35 and Sarah is 9. Hopefully this helps:)
Answer by JBarnum(2146) (Show Source): You can put this solution on YOUR website!
given
m=5s-10
m+s=44
substitution
5s-10+s=44
6s=54
s=9
substitution
m=45-10
m=35
m=michelle
s=sarah
RELATED QUESTIONS
Mary’s grandmother’s age is 11 years less than 9 times mary’s age. The sum of their (answered by ikleyn)
The sum of Victor’s and Ellen’s age is 40 years. Victor’s age 10 years from now will be 1 (answered by oberobic)
Lee's age is 15 years less than half Bob's age. If the sum of their ages is 9, find both... (answered by VFBundy)
Phoebe’s age is 5 more than twice her brother’s age 10 years ago. The sum of their... (answered by trevorgiehl)
Kim is 2 years less than three times Beverly;s age. If the sum of their ages is 42, find... (answered by addingup)
Jan's age is three years less than twice Tritt's age. The sum of their ages is 30. Find... (answered by josgarithmetic)
Shelias age is 2 years more than twice Nicole's age. The sum of their ages is the same as (answered by addingup)
Shelias age is two years more than twice Nicole’s age. The sum of their ages is the same... (answered by josmiceli,MathTherapy)
Jan's age is 3 years less than twice Tritt`s age. The sum of their ages is 30. (answered by jorel555)