SOLUTION: Diophantus of Alexandria, a third century mathmatician, lived one-sixth of his life in childhood, one-twelfth in his youth, and one-seventh as a bachelor. Then he married and five
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Question 54522: Diophantus of Alexandria, a third century mathmatician, lived one-sixth of his life in childhood, one-twelfth in his youth, and one-seventh as a bachelor. Then he married and five years later had a son. The son died four years before diophantis at half the diophantis was when he himself died. How long did he live?
You can put this solution on YOUR website! Diophantus of Alexandria, a third century mathmatician, lived one-sixth of his life in childhood, one-twelfth in his youth, and one-seventh as a bachelor. Then he married and five years later had a son. The son died four years before diophantis at half the age diophantus was when he himself died. How long did he
live?
:
Let his age at death = x:
:
childhood + youth + young man + 5 yrs + son's age + 4 yrs = His age at death
1/6x + 1/12x + 1/7x + 5 + 1/2x + 4 = x
:
A good common denominator is 84, mult equation by 84 and you get:
14x + 7x + 12x + 420 + 42x + 336 = 84x
75x + 756 = 84x
75x - 84x = - 756
- 9x = - 756
x = -756/-9
x = 84 years old
