You can
put this solution on YOUR website!Let x = Sue's age
x+6 = Leah's age
x+6 + 5 = John's age
Sum of their ages=
x + (x+6) + (x+6+5) = 41
3x +17 = 41
Subtract 17 from each side:
3x + 17 - 17 = 41 - 17
3x = 24
Divide both sides by 3:
x= 8 Sue's age
x+6 = 14 Leah's age
x + 11 = 19 = John's age
Check: Sum of their ages = 8+14+19 = 41
R^2 at SCC