SOLUTION: in three years. michael's uncle will be six times as old as michael was last year. when michael's present age is added to his uncle's present age, the total is 68. how old is each
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Question 541339: in three years. michael's uncle will be six times as old as michael was last year. when michael's present age is added to his uncle's present age, the total is 68. how old is each one now?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
in three years. michael's uncle will be six times as old as michael was last year.
when michael's present age is added to his uncle's present age, the total is 68.
how old is each one now?
:
Let m = Michael's age
Let u = Uncle's age
:
Write an equation for each statement:
:
"in three years. michael's uncle will be six times as old as michael was last year.
u + 3 = 6(m - 1)
u + 3 = 6m - 6
u = 6m - 6 - 3
u = 6m - 9
:
"when michael's present age is added to his uncle's present age, the total is 68.
m + u = 68
Replace u with (6m-9)
m + 6m - 9 = 68
7m = 68 + 9
7m = 77
m = 77/7
m = 11 yrs is M's present age
then
68 - 11 = 57 yrs is Uncle's present age
:
:
Check our solutions in the statement:
in three years. michael's uncle will be six times as old as michael was last year.
57 + 3 = 6(11-1)
60 = 6(10); confirms our solutions
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