SOLUTION: Mary is three years younger than three times Emily's age. The sum of their ages is 53. Find their ages.
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Question 533630: Mary is three years younger than three times Emily's age. The sum of their ages is 53. Find their ages.
Answer by Maths68(1474) (Show Source): You can put this solution on YOUR website!
Let
Present age of Mary = m
Present age of Emily = e
Mary is three years younger than three times Emily's age
m=3e-3............(1)
The sum of their ages is 53
m+e=53.............(2)
Put the value of m from (1) to (2)
(3e-3)+e=53
3e-3+e=53
4e=53+3
4e=56
e=56/4
e=14
Put the value of e in (1)
m=3e-3
m=3(14)-3
m=42-3
m=39
Present age of Mary = m = 39
Present age of Emily = e = 14
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