SOLUTION: The ancient one is 40 years older than the youngster. 10 years agos, the age of the ancient one was 22 years greater than seven times the age of youngster then. How old are both of
Algebra.Com
Question 521502: The ancient one is 40 years older than the youngster. 10 years agos, the age of the ancient one was 22 years greater than seven times the age of youngster then. How old are both of them today?
Found 3 solutions by stanbon, Maths68, MathTherapy:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The ancient one is 40 years older than the youngster. 10 years agos, the age of the ancient one was 22 years greater than seven times the age of youngster then. How old are both of them today?
------
Equations:
a = y + 40
(a-10) = 5y+22
---
Substitute for "a" and solve for "y":
(y+40-10) = 5y+22
---
y + 30 = 5y + 22
4y = 8
y = 2 yrs old (the younster's age now)
---
Solve for "a":
a = y + 40
a = 2+40 = 42 yrs old (the ancient's age now)
----
Cheers,
Stan H.
=============
Answer by Maths68(1474) (Show Source): You can put this solution on YOUR website!
Let
Present age of ancient DISABLED_event_one= a
Present age of youngste = b
The ancient one is 40 years older than the youngster
a=b+40..........(1)
10 years ago,
age of ancient one was = a-10
age of youngste was = b-10
Then,the age of the ancient one was 22 years greater than seven times the age of youngster
a-10=7(b-10)+22
a-10=7b-70+22
a=7b-70+22+10
a=7b-70+32
a=7b-38..........(2)
Put the value of a from (1) to (2)
b+40=7b-38
b-7b=-38-40
-6b=-78
-6b/-6=-78/-6
b=-78/-6
b=13
put the value of b (1)
a=b+40
a=13 + 40
a=53
Present age of ancient DISABLED_event_one= a = 53 years old
Present age of youngste = b = 13 years old
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
The ancient one is 40 years older than the youngster. 10 years agos, the age of the ancient one was 22 years greater than seven times the age of youngster then. How old are both of them today?
Let ancient's age be A, and youngster's, Y
Then, A = Y + 40 -------- eq (i)
A – 10 = 7(Y – 10) + 22 ----- A – 7Y = - 38 -------- eq (ii)
Y + 40 – 7Y = - 38 ------- Substituting Y + 40 for A in eq (ii)
- 6Y = - 78
Y, or youngster = , or years-old
A = 13 + 40 ------ Substituting 13 for Y in eq (i)
A, or ancient's age =
-------
Check
-------
Ancient is 40 years older than youngster
53 = 40 + 13
53 = 53 (TRUE)
10 years ago, ancient was 22 years older than 7 times youngster's age then
53 - 10 = 7(13 - 10) + 22
43 = 7(3) + 22
43 = 21 + 22
43 = 43 (TRUE)
Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
RELATED QUESTIONS
Ten years ago Mike was one and a half times the age of Julia. Now Mike is 5 years older... (answered by addingup)
Dan's father was forty years older when the son was 12 years old. How many years must be... (answered by ankor@dixie-net.com)
leslie is 10 years older than twice anthony's age, whereas nancy is 40 years less than... (answered by josgarithmetic)
The sum of David's age and Ben's age is 40. Ann is 3 years older than David. David is 4... (answered by ikleyn)
John was 10 years older than Jane 10 years ago. Jim was 5 years younger than John 10... (answered by mananth)
10 years ago, Mona's mother was 4 times older than her daughter. After 10 years, the... (answered by ikleyn)
Q . A man is 24 years older than his son.In two years,his age will be twicethe age of his (answered by stanbon)
Tina is 24 years older than Reena. 10 years before Tina's age was five times the age of... (answered by sachi)
1. Ayie is 8 years older than Icas. The sum of their ages is 32. How old is each now?
2. (answered by mananth)