# SOLUTION: John is 10 years older than Chris. In 2 years John will be twice as old as Chris. How old are they now?

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 Click here to see ALL problems on Age Word Problems Question 520238: John is 10 years older than Chris. In 2 years John will be twice as old as Chris. How old are they now?Answer by Maths68(1474)   (Show Source): You can put this solution on YOUR website!Let Present age of John = j Present age of Chris = c John is 10 years older than Chris. j=c+10 ..........(1) In 2 years John will be = j + 2 Chris will be = c + 2 Then, John will be twice as old as Chris. j + 2 = 2(c + 2) j + 2 = 2c + 4 j = 2c + 4 - 2 J = 2c + 2 .............(2) Put the value of j from (1) to (2) c+10 = 2c + 2 .............(2) c-2c=2-10 -c=-8 Multiply by -1 both sides c=8 Put the value of c in (1) j = 8 + 10 j = 18 Present age of John = j = 18 years old Present age of Chris = c = 8 years old