SOLUTION: alice is 4 years younger than her husband, and twice as old now as she was 17 years ago. how old are they?

Question 519884: alice is 4 years younger than her husband, and twice as old now as she was 17 years ago. how old are they?
Found 2 solutions by mananth, stanbon:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Husband --------x years
alice-----------x-4 years
17 years ago
Alice = x-4-17=>x-21
x-4=2(x-21)
x-4=2x-42
2x-x=38
x=38 years
husband 38 years
Alice = 34 years
m.ananth@hotmail.ca
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
alice is 4 years younger than her husband, and twice as old now as she was 17 years ago. how old are they?
-------------------------------
Equations:
a = h-4
a = 2*17 = 34
----------------------
Substitute for "a" and solve for "h":
34 = h-4
husband's age = 34+4 = 38 yrs of age
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Cheers,
Stan H.
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