# SOLUTION: The age of the father is 5 times the age of his son. After 18 years, the age of the father will be twice his sons age. Find their present ages.

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 Question 519229: The age of the father is 5 times the age of his son. After 18 years, the age of the father will be twice his sons age. Find their present ages. Answer by Maths68(1474)   (Show Source): You can put this solution on YOUR website!Let Present age of Father = f Present age of Son = s The age of the father is 5 times the age of his son. f=5s.........(1) After 18 years, Age of Father = f+18 Age of Son = s+18 Then, the age of the father will be twice his sons age. f+18=2(s+18) f+18=2s+36 f=2s+36-18 f=2s+18............(1) Substitute the value of f in (2) from (1) 5s=2s+18 5s-2s=18 3s=18 3s/3=18/3 s=6 Substitute the value of s in (1) f=5s f=5(6) f=30 Present age of Father = f = 30 years old Present age of Son = s = 6 years old