SOLUTION: Mr. Jackson is 13 years less than three times as old as his son. Six years ago he was fourteen years more than twice as old as his son was then. Find each of their ages today

Question 515993: Mr. Jackson is 13 years less than three times as old as his son. Six years ago he was fourteen years more than twice as old as his son was then. Find each of their ages today
Answer by Maths68(1474) (Show Source): You can put this solution on YOUR website!
Let
Present age of Mr. Jackson = j
Present age of Son = s

Mr. Jackson is 13 years less than three times as old as his son.
j=3s-13........(1)
Six years ago he was fourteen years more than twice as old as his son was then.
j-6=2(s-6)+14
j-6=2s-12+14
j-6=2s+2
j=2s+2+6
j=2s+8..............(2)
Put the value of j from (1) to (2)
3s-13=2s+8
3s-2s=8+13
s=21
Put the value of s in (1)
j=3s-13........(1)
j=3(21)-13
j=63-13
j=50

Present age of Mr. Jackson = j = 50 years old
Present age of Son = s = 21 years old

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