# SOLUTION: two years ago father was 3 times as old as his son and 2 year hence,twice his age will be equal to 5 times that of his son find present age ?

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 Question 515636: two years ago father was 3 times as old as his son and 2 year hence,twice his age will be equal to 5 times that of his son find present age ?Answer by Maths68(1474)   (Show Source): You can put this solution on YOUR website!Let Present age of Father = f Present age of Son = s Two years ago f-2=s-2 Father was 3 times as old as his son f-2=3(s-2) f-2=3s-6 f=3s-6+2 f=3s-4............(1) and 2 year hence, f+2=s+2 then twice his age will be equal to 5 times that of his son 2(f+2)=5(s+2) 2f+4=5s+10 2f=5s+10-4 2f=5s+6.............(2) Put the value of f in (2) from (1) 2(3s-4)=5s+6 6s-8=5s+6 6s-5s=6+8 s=14 Put the value of s in (1) f=3s-4............(1) f=3(14)-4 f=42-4 f=38 Present age of Father = f = 38 years old Present age of Son = s = 14 years old