# SOLUTION: Annilee's present age is two-thirds of Jessie's present age. In 4 years the sum of their ages will be 73 years. Find their present ages.

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 Question 500179: Annilee's present age is two-thirds of Jessie's present age. In 4 years the sum of their ages will be 73 years. Find their present ages. Answer by Maths68(1474)   (Show Source): You can put this solution on YOUR website!Let Present age of Annilee=a Present age of Jessie=j Annilee's present age is two-thirds of Jessie's present age a= (2/3)j a=2j/3 ................(1) In 4 years means we have to add 4 in the present ages of both a+4=j+4 then the sum of their ages will be 73 years (a+4)+(j+4)=73 a+4+j+4=73 a+j+8=73 a+j=73-8 a+j=65..............(2) Put the value of a from (1) to (2) a+j=65 2j/3 + j = 65 Multiply by 3 both sides of above equation 2j+3j=195 5j=195 Divide by 5 both sides of the equations 5j/5=195/5 j=39 Put the value of j in (1) a=2j/3 a=(2*39)/3 a=78/3 a=26 Present age of Annilee= 26 Present age of Jessie= 39