SOLUTION: Linda is 3 more than 2 times the age of Jane. In five years the sum of their ages will be 28. What is Linda's age at present ?

Question 487014: Linda is 3 more than 2 times the age of Jane. In five years the sum of their ages will be 28. What is Linda's age at present ?
Found 2 solutions by John10, josmiceli:
Answer by John10(297) (Show Source): You can put this solution on YOUR website!
Let x be Linda's age and y is Jane's age at present.
x = 3 + 2y
In five years, their ages sum is 28
(x + 5) + (y + 5) = 28
(3 + 2y + 5) + y + 5 = 28
3y + 13 = 28
3y = 28 - 13
3y = 15
y = 15/3
y = 5
x = 3 + 2y = 3 + 2(5) = 3 + 10 = 13
Thus Linda is 13 years old.
john10:)
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = Linda's age now
Let = Jane's age now
given:
(1)
(2)
---------------------
From (1)
(1)
From (2)
(2)
Subtract (1) from (2)
(2)
(1)

And, since
(2)
(2)
(2)
Linda's present age is 13
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