# SOLUTION: Eunice is 2 years less than 3 times her brother's age. Four years from now, Eunice will be twice as old as her brother. How old are they now?

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Age -> SOLUTION: Eunice is 2 years less than 3 times her brother's age. Four years from now, Eunice will be twice as old as her brother. How old are they now?      Log On

 Ad: Over 600 Algebra Word Problems at edhelper.com Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Word Problems: Age Solvers Lessons Answers archive Quiz In Depth

 Question 467533: Eunice is 2 years less than 3 times her brother's age. Four years from now, Eunice will be twice as old as her brother. How old are they now?Answer by mananth(12270)   (Show Source): You can put this solution on YOUR website!Brother's age be x Eunice's age = 3x-2 after 4 years Brother will be x+4 Eunice will be (3x-2)+4= 3x+2 3x+2 = 2( x+4) 3x+2=2x+8 x=6 brother's age Eunice age = 3x-2==> 3*6-2=16 years