SOLUTION: bill is 6 years older than Tom. Three years ago Bill's age was four times Tom's age. What is the age of each boy?

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 Question 461774: bill is 6 years older than Tom. Three years ago Bill's age was four times Tom's age. What is the age of each boy?Answer by algebrahouse.com(1283)   (Show Source): You can put this solution on YOUR website!"bill is 6 years older than Tom. Three years ago Bill's age was four times Tom's age. What is the age of each boy?" x = Tom's age now x + 6 = Bill's age now x - 3 = Tom's age 3 years ago {subtracted 3 from present age} x + 3 = Bill's age 3 years ago {subtracted 3 from present age} x + 3 = 4(x - 3) {three years ago Bill's age was four times Tom's age} x + 3 = 4x - 12 {used distributive property} 3 = 3x - 12 {subtracted x from both sides} 3x = 15 {added 12 to both sides} x = 5 {divided both sides by 3} x + 6 = 11 {substituted 5, in for x, into x + 6} Tom is 5 Bill is 11 www.algebrahouse.com