SOLUTION: seven years ago father's age was 5 times of his son's age. 14 years hence their age will be the ratio of 7:3. what is the present age of father
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Question 433361: seven years ago father's age was 5 times of his son's age. 14 years hence their age will be the ratio of 7:3. what is the present age of father
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
seven years ago father's age was 5 times of his son's age. 14 years hence their age will be the ratio of 7:3. what is the present age of father
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(f-7)=5(s-7)
(f+14)/(s+14) = 7/3
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Rearrange:
f = 5s-28
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Substitute and solve for "s":
(5s-28+14)/(s+14) = 7/3
Cross multiply:
3(5s-14) = 7(s+14)
15s-42 = 7s+98
8s = 140
s = 35/2 (son's age now)
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Solve for "f":
f = 5s-28
f = 5*35/2-28
f = 175/2-28
f = 59.5 (father's age now)
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Cheers,
Stan H.
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