SOLUTION: A mother's age is 3 years more than the square of her daughter's age. In 18 years time she will be twice her daughter's age. What are the mother's and daughter's ages now?
It is
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Question 432240: A mother's age is 3 years more than the square of her daughter's age. In 18 years time she will be twice her daughter's age. What are the mother's and daughter's ages now?
It is a question for applicable Quadratics. I know what the answer is, I just don't know how to solve it.
I've tried:
and
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
in the 2nd equation, remember that the daughter is also 18 years older ___ m + 18 = 2(d + 18)
m = 2d + 18
substituting ___ 2d + 18 = d^2 + 3
0 = d^2 - 2d - 15
factoring ___ 0 = (d - 5)(d + 3)
d + 3 = 0 ___ d = -3 ___ negative value not realistic
d - 5 = 0 ___ d = 5
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