SOLUTION: �There are seven less than twice the marbles in Tim�s box as there are in Amelia�s box. Chris has six more marbles than Amelia. How many marbles does Amelia have if together the th

Question 422437: �There are seven less than twice the marbles in Tim�s box as there are in Amelia�s box. Chris has six more marbles than Amelia. How many marbles does Amelia have if together the three of them have 95 marbles?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
There are seven less than twice the marbles in Tim�s box as there are in Amelia�s box.
t = 2a-7
--------
Chris has six more marbles than Amelia.
c = a+6
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How many marbles does Amelia have if together the three of them have 95 marbles?
t + c + a = 95
=========================
Substitute for "t" and for "c" and solve for "a":
(2a-7)+(a+6)+a = 95
4a -1 = 95
4a = 96
a = 24 (amelia's marbles)
---
t = 2a-7 = 41 (tim's marbles)
----
c = a + 6 = 30 (chris's marbles)
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Cheers,
Stan H.
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