SOLUTION: susan is twice as old as her brother. five years ago susan was 3 times as old as her brother. find her age
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Question 413165: susan is twice as old as her brother. five years ago susan was 3 times as old as her brother. find her age
Answer by algebrahouse.com(1659) (Show Source): You can put this solution on YOUR website!
"susan is twice as old as her brother. five years ago susan was 3 times as old as her brother. find her age"
x = brother's age now
2x = Susan's age now
x - 5 = brother's age 5 years ago
2x - 5 = Susan's age 5 years ago
2x - 5 = 3(x - 5) {five years ago susan was 3 times as old as her brother}
2x - 5 = 3x - 15 {used distributive property}
2x + 10 = 3x {added 15 to both sides}
x = 10 {subtracted 2x from both sides}
2x = 20 {Susan's age now}
Susan is 20 now
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