SOLUTION: Please help me solve this question: "A father is four times as old as his son. In four years' time their combined age will be 48 years. How old are they now?"

Question 392630: Please help me solve this question:
"A father is four times as old as his son. In four years' time their combined age will be 48 years. How old are they now?"
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A father is four times as old as his son. In four years' time their combined age will be 48 years. How old are they now?"
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Equations:
f = 4s
(f+4)+(s+4) = 48
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Substitute for "f" and solve for "s":
(4s+4)+(s+4) = 48
5s+8 = 48
5s = 40
s = 8 yrs old (son's age now)
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Solve for "f":
f = 4s
f = 4*8 = 32 yrs old (father's age now)
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Cheers,
Stan H.
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