SOLUTION: A BOAT TRAVELS 60 KM UPSTREAM (AGAINST THE CURRENT) IN 5 HOURS. THE BOAT TRAVELS THE SAME DISTANCE DOWNSTREAM IN 3 HOURS. WHAT IS THE RATE OF THE BOAT IN STILL WATER? WHAT S TH RAT

Question 389629: A BOAT TRAVELS 60 KM UPSTREAM (AGAINST THE CURRENT) IN 5 HOURS. THE BOAT TRAVELS THE SAME DISTANCE DOWNSTREAM IN 3 HOURS. WHAT IS THE RATE OF THE BOAT IN STILL WATER? WHAT S TH RATE OF THE CURREN?

Answer by sudhanshu_kmr(1152) (Show Source): You can put this solution on YOUR website!
According to question,
speed of boat in against the current = 60/5 =12 km/h
speed of boat with the current = 60/3 = 20 km/h

let the speed of boat in still water = x km/h and rate of current is : y km/h
then x+y =20... (1) (speed of boat with the current)
and x-y = 12 .... (2) (speed against the current)
now, add these two equations..
2x =32 => x =16
and y=4
speed of boat in still water =16 km/h and speed of current is 4km/h.

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