Hi,  

 a father is four times as old as the sum of the ages of his two sons      

Let x and 4x represent the sum of son's ages and father's age NOW

Question States***

 4x + 8 = 2[x+16]

Solving for x

 4x + 8 = 2x + 32

    2x = 24

     x = 12, the sum of the two son's ages NOW.  Father is 48.  (4*12)



CHECKING our Answer***(8 years from NOW)

 56 = 2*28 = 56 

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